Extracting file from zip archive in Python 2.6.1

Hello everyone, I'm having an issue specifying the path for extracting files from a .zip archive. In my method, I have: zip_file.extract(zip_name + '/' + thumbnail_image, thumbnail_path) What is happening is that the extract method is creating a folder with the name of 'zip_name' and extracting

Problem using compileall

I'm having a slight problem with pre-compiling some files for distribution that I'm not sure where to even look for. An excerpt from an output: C:\mother\Python24\core\application\sysconfig>python -m compileall . Listing . ... Compiling .\BulkListClass.py ... Sorry: TypeError: ('c

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