py <[EMAIL PROTECTED]> wrote:
> Thanks...I think base64 will work just fine...and doesnt seem to have
> 45 byte limitations, etc.
Sure, base64 is a better encoding by all criteria, unless you
specifically need to use uu encoding for compatibility with other old
software.
Alex
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Thanks...I think base64 will work just fine...and doesnt seem to have
45 byte limitations, etc.
Thanks.
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py <[EMAIL PROTECTED]> wrote:
> Alex Martelli wrote:
> I suggest a redesign...!
>
>
> What would you suggest? I have to encode/decode in chunks b/c of the
> 45 byte limitation.
Not quite:
>>> s=45*'v'
>>> a=binascii.b2a_uu(s)
>>> len(a)
62
>>> b=binascii.a2b_uu(a)
>>> len(b)
45
>>> b==s
True
"py" wrote:
> What would you suggest? I have to encode/decode in chunks b/c of the
> 45 byte limitation.
so use 45-byte chunks, instead of one-byte chunks.
but why are you using UU encoding in a nonstandard way ? why not just
use the "uu" module to do the chunking for you? the third example o
Alex Martelli wrote:
I suggest a redesign...!
What would you suggest? I have to encode/decode in chunks b/c of the
45 byte limitation.
Thanks.
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py <[EMAIL PROTECTED]> wrote:
...
> """data is a string"""
> if len(data) > 45:
> tmp = []
> for c in data:
> tmp.append(binascii.b2a_uu(c))
You can't decode b2a-encoded data character by character, blindly, as
you're trying to to here. Each character in the
Note that you can use the 'uu' encoding, which will handle
arbitrary-length input and give multi-line uuencoded output, including
the 'begin' and 'end' lines:
>>> print ("\377" * 120).encode("uu")
begin 666
M
M
Alex Martelli wrote:
> binascii.b2a_uu only works for up to 45 bytes at once; but if you were
> feeding it more than 45 bytes, this should raise a binascii.Error
> itself.
> Definitely not, given the above limit. But I still don't quite
> understand the exact mechanics of the error you're getting.
py <[EMAIL PROTECTED]> wrote:
...
> encoded.append(binascii.b2a_uu(stringToEncode))
binascii.b2a_uu only works for up to 45 bytes at once; but if you were
feeding it more than 45 bytes, this should raise a binascii.Error
itself.
> ..any idea why this is happening? Anyone successfully use
Hi,
I am encoding a string such as...
[code]
data = someFile.readlines()
encoded = []
for line in data:
encoded.append(binascii.b2a_uu(stringToEncode))
return encoded
[/code]
...I then try to decode this by...
[code]
def decode(data):
result = []
for val in data:
result.app
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