>> Why do you think they are not?
>
> Because they aren't. You even mentioned that a few operations that
> aren't atomic.
OTOH, the OP specifically asked for .append() and .pop(), which are
atomic.
Regards,
Martin
--
http://mail.python.org/mailman/listinfo/python-list
> Why do you think they are not?
Because they aren't. You even mentioned that a few operations that
aren't atomic. If operations are atomic it isn't necessarily because
of the design of the list, but the design of CPython. More
specifically the GIL. I don't mean to imply that you can't get a
multi
>> My question is -- are python list operations atomic? If they are not,
>> then I assume I need to put some mutual exclusion around the append()
>> and pop() calls ?
>
> They are not, but there is one included in the standard library:
> http://docs.python.org/dev/lib/module-Queue.html
Why do you
> My question is -- are python list operations atomic? If they are not,
> then I assume I need to put some mutual exclusion around the append()
> and pop() calls ?
They are not, but there is one included in the standard library:
http://docs.python.org/dev/lib/module-Queue.html
Matt
--
http://mai
> I have two threads that share a python list. One thread adds to the
> list with append(), the other thread removes items with pop().
>
> My question is -- are python list operations atomic?
Yes, they are in the current implementation of CPython (all versions).
Notice that not *all* operations a
On Aug 15, 1:36 pm, Scott <[EMAIL PROTECTED]> wrote:
> I have two threads that share a python list. One thread adds to the
> list with append(), the other thread removes items with pop().
>
> My question is -- are python list operations atomic? If they are not,
> then I assume I need to put some mu
I have two threads that share a python list. One thread adds to the
list with append(), the other thread removes items with pop().
My question is -- are python list operations atomic? If they are not,
then I assume I need to put some mutual exclusion around the append()
and pop() calls ?
Thanks,