--- On Thu, 11/25/10, MRAB wrote:
> >
> Look at the spans:
>
> >>> for m in re.finditer('((.d.)*)*', 'adb'):
> print(m.span())
>
>
> (0, 3)
> (3, 3)
>
> There's an non-empty match followed by an empty match.
If you read my first post, it should be apparent that
that the empty string
On 25/11/2010 16:44, Yingjie Lan wrote:
--- On Thu, 11/25/10, MRAB wrote:
re.findall performs multiple searches, each starting where
the previous
one finished. The first match started at the start of the
string and
finished at its end. The second match started at that point
(the end of
the stri
--- On Thu, 11/25/10, MRAB wrote:
> re.findall performs multiple searches, each starting where
> the previous
> one finished. The first match started at the start of the
> string and
> finished at its end. The second match started at that point
> (the end of
> the string) and found another match,
On 25/11/2010 11:32, Yingjie Lan wrote:
I know many experts will say I don't have understanding...but let me pay this
up front as my tuition.
Here are some puzzling results I have got (I am using Python 3, I suppose
similar results for python 2).
When I do the following, I got an exception:
I know many experts will say I don't have understanding...but let me pay this
up front as my tuition.
Here are some puzzling results I have got (I am using Python 3, I suppose
similar results for python 2).
When I do the following, I got an exception:
>>> re.findall('(d*)*', 'adb')
>>> re.finda
