Philipp Kraus wrote:
> I have create a short script:
>
> -
> #!/usr/bin/env python
>
> import re, urllib2
>
>
> def URLReader(url) :
> f = urllib2.urlopen(url)
> data = f.read()
> f.close()
> return data
>
>
> print re.match( "\.*\<\/small\>",
> URLReader("http://sour
Hi,
On 2014-08-16 09:01:57 +, Peter Otten said:
Philipp Kraus wrote:
The code works till last week correctly, I don't change the pattern.
Websites' contents and structure change sometimes.
My question is, can it be a problem with string encoding?
Your regex is all-ascii. So an encod
Philipp Kraus wrote:
> The code works till last week correctly, I don't change the pattern.
Websites' contents and structure change sometimes.
> My question is, can it be a problem with string encoding?
Your regex is all-ascii. So an encoding problem is very unlikely.
> found = re.search( "
Philipp Kraus wrote:
> The code works till last week correctly, I don't change the pattern. My
> question is, can it be
> a problem with string encoding? Did I mask the question mark and quotes
> correctly?
If you didn't change the code, how could the *exact same code* not mask the
question mark
In article ,
Philipp Kraus wrote:
> The code works till last week correctly, I don't change the pattern.
OK, so what did you change? Can you go back to last week's code and
compare it to what you have now to see what changed?
> My question is, can it be a problem with string encoding? Did I
On 2014-08-16 00:48:46 +, Roy Smith said:
In article ,
Philipp Kraus wrote:
found = re.search( "http://sourceforge.net/projects/boost/files/boost/";)
)
if found == None :
raise MyError.StopError("Boost Download URL not found")
But found is always None, so I cannot get the correc
In article ,
Philipp Kraus wrote:
> found = re.search( " href=\"/projects/boost/files/latest/download\?source=files\"
> title=\"/boost/(.*)",
> Utilities.URLReader("http://sourceforge.net/projects/boost/files/boost/";)
> )
> if found == None :
> raise MyError.StopError("Boost Download U
Hello,
I have defined a function with:
def URLReader(url) :
try :
f = urllib2.urlopen(url)
data = f.read()
f.close()
except Exception, e :
raise MyError.StopError(e)
return data
which get the HTML source code from an URL. I use this to get a part of
a HTML
