On Fri, Apr 16, 2010 at 15:16, Terry Reedy wrote:
> On 4/16/2010 9:41 AM, J wrote:
>>
>> Ok... I know pretty much how .extend works on a list... basically it
>> just tacks the second list to the first list... like so:
>>
> lista=[1]
> listb=[2,3]
> lista.extend(listb)
> print lista
On 4/16/2010 9:41 AM, J wrote:
Ok... I know pretty much how .extend works on a list... basically it
just tacks the second list to the first list... like so:
lista=[1]
listb=[2,3]
lista.extend(listb)
print lista;
[1, 2, 3]
This shows right here that lista is extended in place. If you are not
On Sat, 2010-04-17 at 00:37 +1000, Lie Ryan wrote:
> On 04/16/10 23:41, J wrote:
> > So, what I'm curious about, is there a list comprehension or other
> > means to reduce that to a single line?
>
> from itertools import chain
> def printout(*info):
> print '\n'.join(map(str, chain(*info)))
>
On 04/16/10 23:41, J wrote:
> Ok... I know pretty much how .extend works on a list... basically it
> just tacks the second list to the first list... like so:
>
lista=[1]
listb=[2,3]
lista.extend(listb)
print lista;
> [1, 2, 3]
>
> what I'm confused on is why this returns None:
J a écrit :
Ok... I know pretty much how .extend works on a list... basically it
just tacks the second list to the first list... like so:
lista=[1]
listb=[2,3]
lista.extend(listb)
print lista;
[1, 2, 3]
what I'm confused on is why this returns None:
So why the None? Is this because what's
Ok... I know pretty much how .extend works on a list... basically it
just tacks the second list to the first list... like so:
>>> lista=[1]
>>> listb=[2,3]
>>> lista.extend(listb)
>>> print lista;
[1, 2, 3]
what I'm confused on is why this returns None:
>>> lista=[1]
>>> listb=[2,3]
>>> print li
