My apologies to the respondents - I failed to screen my test cases
before kicking them out to the global python-list. but yes, the 'X'
character in my test case was a mistake on my part. I'll give group()
a shot.
ct
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Steven D'Aprano wrote:
Assuming that you want to find runs of \u escapes, simply use
non-capturing parentheses:
pat = re.compile(u"(?:\\\u[0-9A-F]{4})")
Doesn't work for me:
pat = re.compile(u"(?:\\\u[0-9A-F]{4})")
it helps if you cut and paste the right line... here's a better v
On Wed, 17 Sep 2008 09:27:47 -0400, christopher taylor wrote:
> hello python-list!
>
> the other day, i was trying to match unicode character sequences that
> looked like this:
>
> \\uAD0X...
It is not clear what this is supposed to be. Is that matching a literal
pair of backslashes, or a sing
On Wed, 17 Sep 2008 15:56:31 +0200, Fredrik Lundh wrote:
> Assuming that you want to find runs of \u escapes, simply use
> non-capturing parentheses:
>
> pat = re.compile(u"(?:\\\u[0-9A-F]{4})")
Doesn't work for me:
>>> pat = re.compile(u"(?:\\\u[0-9A-F]{4})")
UnicodeDecodeError: 'unico
christopher taylor wrote:
my issue, is that the pattern i used was returning:
[ '\\uAD0X', '\\u1BF3', ... ]
when i expected:
[ '\\uAD0X\\u1BF3', ]
the code looks something like this:
pat = re.compile("(\\\u[0-9A-F]{4})+", re.UNICODE|re.LOCALE)
#print pat.findall(txt_line)
results = pat.find
On Wed, 17 Sep 2008 09:27:47 -0400, christopher taylor wrote:
> the other day, i was trying to match unicode character sequences that
> looked like this:
>
> \\uAD0X...
>
> my issue, is that the pattern i used was returning:
>
> [ '\\uAD0X', '\\u1BF3', ... ]
>
> when i expected:
>
> [ '\\uAD0X
hello python-list!
the other day, i was trying to match unicode character sequences that
looked like this:
\\uAD0X...
my issue, is that the pattern i used was returning:
[ '\\uAD0X', '\\u1BF3', ... ]
when i expected:
[ '\\uAD0X\\u1BF3', ]
the code looks something like this:
pat = re.compile
