On Dec 17, 2:31 am, Paul McGuire <[EMAIL PROTECTED]> wrote:
> On Dec 17, 1:18 am, "bambam" <[EMAIL PROTECTED]> wrote:
>
>
>
>
>
> > I wish to create a generic container object, devlist, such that
>
> > devlist.method(arguments)
>
> > runs as
>
> > for each dev in devlist.pool:
> > d
"Diez B. Roggisch" <[EMAIL PROTECTED]> writes:
>> In any case, it is not possible, because the instance method cannot
>> know whether its result is being assigned to a name or just thrown
>> away.
>
> This isn't entirely correct - there _are_ ways to know.
>
> http://aspn.activestate.com/ASPN/Cook
Steven D'Aprano wrote:
> On Mon, 17 Dec 2007 18:18:11 +1100, bambam wrote:
>
>> I wish to create a generic container object, devlist, such that
>>
>> devlist.method(arguments)
>>
>> runs as
>>
>> for each dev in devlist.pool:
>> dev.method(arguments)
>>
>> and
>> s = devli
On Mon, 17 Dec 2007 18:18:11 +1100, bambam wrote:
> I wish to create a generic container object, devlist, such that
>
> devlist.method(arguments)
>
> runs as
>
> for each dev in devlist.pool:
> dev.method(arguments)
>
> and
> s = devlist.method(arguments)
>
> runs as
>
>
On Dec 17, 1:18 am, "bambam" <[EMAIL PROTECTED]> wrote:
> I wish to create a generic container object, devlist, such that
>
> devlist.method(arguments)
>
> runs as
>
> for each dev in devlist.pool:
> dev.method(arguments)
>
> and
> s = devlist.method(arguments)
>
> runs as
>
>
I wish to create a generic container object, devlist, such that
devlist.method(arguments)
runs as
for each dev in devlist.pool:
dev.method(arguments)
and
s = devlist.method(arguments)
runs as
for each dev in devlist.pool:
s.append(dev.method(arguments))
...but
