Florian Schulze wrote:
> See the following results:
>
> Python 2.3.5 (#62, Feb 8 2005, 16:23:02) [MSC v.1200 32 bit (Intel)] on
> win32
> Type "help", "copyright", "credits" or "license" for more information.
>
import re
s = "1"
re.sub('1','\\n',s)
>
> '\n'
>
'\\n'
>
> '\
See the following results:
Python 2.3.5 (#62, Feb 8 2005, 16:23:02) [MSC v.1200 32 bit (Intel)] on
win32
Type "help", "copyright", "credits" or "license" for more information.
>>> import re
>>> s = "1"
>>> re.sub('1','\\n',s)
'\n'
>>> '\\n'
'\\n'
>>> re.sub('1',r'\\n',s)
'\\n'
>>> s.replace('1',
