Here is what you want for printing python source filename:
print __file__
> On Tuesday, June 22, 2010 12:44 PM Peng Yu wrote:
> I want to print filename and line number for debugging purpose. So far
> I only find how to print the line number but not how to print
> filename.
>
> import inspect
>
On Jun 24, 4:07 am, Peng Yu wrote:
> %(module)s only print to "__init__". However, I need the fullname
> a.b.__init__. I looked at the manual, but I don't see what format
> string I should supply. Would you please let me know?
>
Did you look at this part of the documentation?
http://docs.python.
On Wed, Jun 23, 2010 at 8:07 PM, Peng Yu wrote:
> I tried to put the above code in a module. Say in a.b.__init__.py
>
> %(module)s only print to "__init__". However, I need the fullname
> a.b.__init__. I looked at the manual, but I don't see what format
> string I should supply. Would you please
On Tue, Jun 22, 2010 at 12:13 PM, Stephen Hansen
wrote:
> On 6/22/10 9:44 AM, Peng Yu wrote:
>> Also, always importing the inspect module and getting the frame and
>> accessing the lineno from the frame is not very convenient to type. Is
>> there a shorter way to access the line number (for exampl
On 6/22/10 10:26 AM, Shashwat Anand wrote:
> begin -
> import logging
> logging.basicConfig(level=logging.DEBUG,format="%(asctime)s"
> "%(levelname)-5.5s [%(name)s %(module)s:%(funcName)s:%(lineno)d]"
> "%(message)s")
>
> def run():
>x = 5
>logging.debug("X = %d" % x)
>
> run()
>
begin -
import logging
logging.basicConfig(level=logging.DEBUG,format="%(asctime)s"
"%(levelname)-5.5s [%(name)s %(module)s:%(funcName)s:%(lineno)d]"
"%(message)s")
def run():
x = 5
logging.debug("X = %d" % x)
run()
- end -
You can probably use string default concatenation
you can use __file__
On Tue, Jun 22, 2010 at 10:14 PM, Peng Yu wrote:
> I want to print filename and line number for debugging purpose. So far
> I only find how to print the line number but not how to print
> filename.
>
> import inspect
> print inspect.currentframe().f_lineno
>
> I found inspec
On 6/22/10 9:44 AM, Peng Yu wrote:
> Also, always importing the inspect module and getting the frame and
> accessing the lineno from the frame is not very convenient to type. Is
> there a shorter way to access the line number (for example, in C++ and
> perl, __LINE__ can be used to access line numb
22:26:51 l0nwlf-MBP:~/Desktop$ cat test.py
print __file__
22:26:55 l0nwlf-MBP:~/Desktop$ python test.py
test.py
On Tue, Jun 22, 2010 at 10:26 PM, Shashwat Anand
wrote:
> you can use __file__
>
>
> On Tue, Jun 22, 2010 at 10:14 PM, Peng Yu wrote:
>
>> I want to print filename and line number fo
I want to print filename and line number for debugging purpose. So far
I only find how to print the line number but not how to print
filename.
import inspect
print inspect.currentframe().f_lineno
I found inspect.getsourcefile(), but I have to supply a class name to
it. I have searched online, but
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