Yingjie Lan wrote:
So, I assume that when the 'def' is executed, any
name occurred will be categorized as either local
or global (maybe nonlocal?).
Actually it happens earlier than that -- the bytecode
compiler does the categorization, and generates different
bytecodes for accessing these thr
Am 17.10.2010 19:51, schrieb TomF:
On 2010-10-17 10:21:36 -0700, Paul Kölle said:
Am 17.10.2010 13:48, schrieb Steven D'Aprano:
On Sun, 17 Oct 2010 03:58:21 -0700, Yingjie Lan wrote:
Hi,
I played with an example related to namespaces/scoping. The result is a
little confusing:
[snip example
On 2010-10-17 10:21:36 -0700, Paul Kölle said:
Am 17.10.2010 13:48, schrieb Steven D'Aprano:
On Sun, 17 Oct 2010 03:58:21 -0700, Yingjie Lan wrote:
Hi,
I played with an example related to namespaces/scoping. The result is a
little confusing:
[snip example of UnboundLocalError]
Python's sco
Am 17.10.2010 13:48, schrieb Steven D'Aprano:
On Sun, 17 Oct 2010 03:58:21 -0700, Yingjie Lan wrote:
Hi,
I played with an example related to namespaces/scoping. The result is a
little confusing:
[snip example of UnboundLocalError]
Python's scoping rules are such that if you assign to a vari
--- On Sun, 10/17/10, Steven D'Aprano
wrote:
> (1) If you assign to a variable *anywhere* in the function,
> it is a local
> *everywhere* in the function.
>
> There is no way to have a variable refer to a local in some
> places of a
> function and a global in other places of the same functi
> From: Nobody
> The determination of local or global is made when the "def"
> statement is
> executed, not when the function is called.
Thanks a lot for your reply, which is of great help!
So, I assume that when the 'def' is executed, any
name occurred will be categorized as either local
or
On Sun, 17 Oct 2010 03:58:21 -0700, Yingjie Lan wrote:
> Hi,
>
> I played with an example related to namespaces/scoping. The result is a
> little confusing:
[snip example of UnboundLocalError]
Python's scoping rules are such that if you assign to a variable inside a
function, it is treated as
On Sun, 17 Oct 2010 03:58:21 -0700, Yingjie Lan wrote:
> I played with an example related to namespaces/scoping. The result is a
> little confusing:
a=1
def f():
> a = a + 1
> return a
>
f()
> UnboundLocalError: local variable 'a' referenced before assignment
If you
Hi,
I played with an example related to namespaces/scoping.
The result is a little confusing:
>>> a=1
>>> def f():
a = a + 1
return a
>>> f()
I suppose I will get 2 ( 'a' is redefined as a local variable, whose value is
obtained by the value of the global variable 'a' plus 1)
