Thank you folks, now I know what I don't know and have a solution.
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On Wednesday 2013 November 20 05:44, Larry Wilson wrote:
> >>> feed.entries[0].w_current
>
> {'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts': u'29.6', 'rain':
> u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed': u'22.2',
> 'winddirection': u'SSW'}
>
>
> in the above I get the sub
On Wednesday 2013 November 20 05:44, Larry Wilson wrote:
> {'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts': u'29.6', 'rain':
> u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed': u'22.2',
> 'winddirection': u'SSW'}
Python 2.7.2 (default, Oct 10 2011, 10:47:36)
[GCC 4.1.2 20061115
Larry Wilson itd...@gmail.com via python.org
10:39 PM (10 hours ago) wrote:
>
> Wanting to parse out the the temperature value in the
> " ElementTree or xml.sax.
Since you aren't building up a complex data structure, xml.sax
will be an OK choice.
Here's a quick and dirty job:
import io
import xm
>>> feed.entries[0].w_current
{'temperature': u'20.3', 'dewpoint': u'18.6', 'windgusts': u'29.6', 'rain':
u'0.6', 'humidity': u'90', 'pressure': u'0.0', 'windspeed': u'22.2',
'winddirection': u'SSW'}
>>>
in the above I get the subitem as shown. How do I extract the label, values
pairs?
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http
On Tuesday 2013 November 19 19:39, Larry Wilson wrote:
> Wanting to parse out the the temperature value in the " element, just after the guid element using ElementTree or xml.sax.
When you get tired of that, take a look at Universal Feedparser, a Python
Package:
http://code.google.com/p/feedparse
Wanting to parse out the the temperature value in the "http://rss.weather.com.au/nsw/newcastle";
===
http://rss.weather.com.au/w.dtd";>
Weather.com.au - Newcastle Weather
http://www.weather.com.au/nsw/newcast
