superpollo writes:
> >>> number = 252509952
> >>> hex(number)
> '0xf0cff00'
> >>>
>
> so i would like a string like '\xf0\xcf\xf0\x00'
def encode(number):
h = '%x' % number
if len(h) % 2 == 1:
h = '0' + h
return h.decode('hex')
--
http://mail.python.org/mailman/listinfo/p
On Jul 24, 3:28 pm, superpollo wrote:
> is there a pythonic and synthetic way (maybe some standard module) to
> "pack" an integer (maybe a *VERY* big one) into a string? like this:
>
> >>> number = 252509952
> >>> hex(number)
> '0xf0cff00'
> >>>
>
> so i would like a string like '\xf0\xcf\
On Jul 24, 7:16 pm, superpollo wrote:
> thanks a lot, but [struct] does not work for large integers:
Since the struct module is designed specifically for C-style structs,
it's definitely not going to handle arbitrary-length integers on its
own. You could chop up your Python (long) integer into C
Piet van Oostrum wrote:
...
You have the string wrong.
oops yea.
But the correct one you get with:
In [67]: import struct
In [68]: number = 252509952
In [69]: struct.pack('>I', number)
Out[69]: '\x0f\x0c\xff\x00'
(Please note that this is big endian)
thanks a lot, but it does not work f
superpollo wrote:
Sebastian Bassi wrote:
On Fri, Jul 24, 2009 at 7:28 PM, superpollo wrote:
is there a pythonic and synthetic way (maybe some standard module) to
"pack"
an integer (maybe a *VERY* big one) into a string? like this:
What do you mean to pack? Maybe Pickle is what you want.
> superpollo (s) wrote:
>s> is there a pythonic and synthetic way (maybe some standard module) to
>s> "pack" an integer (maybe a *VERY* big one) into a string? like this:
> number = 252509952
> hex(number)
>s> '0xf0cff00'
>
>s> so i would like a string like '\xf0\xcf\xf0\x00'
Sebastian Bassi wrote:
On Fri, Jul 24, 2009 at 7:28 PM, superpollo wrote:
is there a pythonic and synthetic way (maybe some standard module) to "pack"
an integer (maybe a *VERY* big one) into a string? like this:
What do you mean to pack? Maybe Pickle is what you want.
import cPickle
variab
On Fri, Jul 24, 2009 at 7:28 PM, superpollo wrote:
> is there a pythonic and synthetic way (maybe some standard module) to "pack"
> an integer (maybe a *VERY* big one) into a string? like this:
What do you mean to pack? Maybe Pickle is what you want.
import cPickle
variable = 124348654333577698
c
is there a pythonic and synthetic way (maybe some standard module) to
"pack" an integer (maybe a *VERY* big one) into a string? like this:
>>> number = 252509952
>>> hex(number)
'0xf0cff00'
>>>
so i would like a string like '\xf0\xcf\xf0\x00'
i wrote some code to do it, so ugly i am ashame
