> No, it removes the association between the name 'item' and the object it is
> currently bound to. In CPython, removing the last such reference will
> cause the object to be gc'ed. In other implementations, actual deletion
> may occur later. You probably should close the files directly and arra
"massimo s." <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
| Hi,
|
| Python 2.4, Kubuntu 6.06. I'm no professional programmer (I am a ph.d.
| student in biophysics) but I have a fair knowledge of Python.
|
| I have a for loop that looks like the following :
|
| for item in long_list
> Relying on the `__del__()` method isn't a good idea because there are no
> really hard guaranties by the language if and when it will be called.
Ok, I read the __del__() docs and I understand using it is not a good
idea.
I can easily add a close_files() method that forces all dangling files
to
> It will delete the *name* `item`. It does nothing to the object that was
> bound to that name. If the name was the only reference to that object, it
> may be garbage collected sooner or later. Read the documentation for the
> `__del__()` method for more details and why implementing such a meth
In <[EMAIL PROTECTED]>, massimo s.
wrote:
> I have a for loop that looks like the following :
>
> for item in long_list:
>foo(item)
>
> def foo(item):
>item.create_blah() #<--this creates item.blah; by doing that it
> opens a file and leaves it open until blah.__del__() is called
On 24 May, 16:40, "massimo s." <[EMAIL PROTECTED]> wrote:
> Now, what I thought is that if I call
>
> del(item)
>
> it will delete item and also all objects created inside item.
Sort of, but it's a bit more subtle. You'll stop the name "item" from
referring to your item - if nothing else refers to
Hi,
Python 2.4, Kubuntu 6.06. I'm no professional programmer (I am a ph.d.
student in biophysics) but I have a fair knowledge of Python.
I have a for loop that looks like the following :
for item in long_list:
foo(item)
def foo(item):
item.create_blah() #<--this creates item.blah;