On Jul 16, 5:05 am, Mark Dickinson <[EMAIL PROTECTED]> wrote:
> On Jul 16, 7:20 am, Mensanator <[EMAIL PROTECTED]> wrote:
>
> > > > ## Combinations with replacement
> > > > ## -
> > > > ## aaa aab aac aad aae abb abc abd abe acc acd ace
> > > > ## add ade aee bbb bbc
On Jul 16, 7:20 am, Mensanator <[EMAIL PROTECTED]> wrote:
> > > ## Combinations with replacement
> > > ## -
> > > ## aaa aab aac aad aae abb abc abd abe acc acd ace
> > > ## add ade aee bbb bbc bbd bbe bcc bcd bce bdd bde
> > > ## bee ccc ccd cce cdd cde cee ddd dde
On Jul 15, 1:44 am, Raymond Hettinger <[EMAIL PROTECTED]> wrote:
> On Jul 14, 1:26 pm, Mensanator <[EMAIL PROTECTED]> wrote:
>
> > ## Combinations with replacement
> > ## -
> > ## aaa aab aac aad aae abb abc abd abe acc acd ace
> > ## add ade aee bbb bbc bbd bbe bcc
On Jul 14, 1:26 pm, Mensanator <[EMAIL PROTECTED]> wrote:
> ## Combinations with replacement
> ## -
> ## aaa aab aac aad aae abb abc abd abe acc acd ace
> ## add ade aee bbb bbc bbd bbe bcc bcd bce bdd bde
> ## bee ccc ccd cce cdd cde cee ddd dde dee eee
> ##
> ##
With the new functions added to itertools in Python 2.6,
I can finally get rid of this monstrosity:
def ooloop6(a, n, perm=True, repl=True):
if (not repl) and (n>len(a)): return
r0 = range(n)
r1 = r0[1:]
if perm and repl: # ok
v = ','.join(['c%s' % i for i in r
