Duncan Booth wrote:
> mk wrote:
>
>> Hm, apparently Python didn't spot that 'spam'*10 in a's values is really
>> the same string, right?
>
> If you want it to spot that then give it a hint that it should be looking
> for identical strings:
>
> >>> a={}
> >>> for i in range(1000):
> ...
On 3/4/2010 6:56 AM, mk wrote:
Bruno Desthuilliers wrote:
Huh? I was under impression that some time after 2.0 range was made to
work "under the covers" like xrange when used in a loop? Or is it 3.0
that does that?
3.0.
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On Mar 4, 12:24 pm, Duncan Booth wrote:
>
> >>> a={}
> >>> for i in range(1000):
> ... a[i]=intern('spam'*10)
>
"intern": another name borrowed from Lisp?
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mk wrote:
> Hm, apparently Python didn't spot that 'spam'*10 in a's values is really
> the same string, right?
If you want it to spot that then give it a hint that it should be looking
for identical strings:
>>> a={}
>>> for i in range(1000):
... a[i]=intern('spam'*10)
should reduc
Bruno Desthuilliers wrote:
mk a écrit :
Obviously, don't try this on low-memory machine:
a={}
for i in range(1000):
Note that in Python 2, this will build a list of 1000 int objects.
You may want to use xrange instead...
Huh? I was under impression that some time after 2.0 range w
Bruno Desthuilliers a écrit :
> mk a écrit :
(snip)
>> So sys.getsizeof returns some 200MB for this dictionary. But according
>> to top RSS of the python process is 300MB. ps auxw says the same thing
>> (more or less).
>>
>> Why the 50% overhead?
Oh, and yes - the interpreter itself, the builtins
mk a écrit :
>
> Obviously, don't try this on low-memory machine:
>
a={}
for i in range(1000):
Note that in Python 2, this will build a list of 1000 int objects.
You may want to use xrange instead...
> ... a[i]='spam'*10
> ...
import sys
sys.getsizeof(a)
> 201326
Obviously, don't try this on low-memory machine:
>>> a={}
>>> for i in range(1000):
... a[i]='spam'*10
...
>>> import sys
>>> sys.getsizeof(a)
201326728
>>> id(a[1])
3085643936L
>>> id(a[100])
3085713568L
>>> ids={}
>>> for i in range(len(a)):
... ids[id(a[i])]=True
...
>>> len(ids.
