Suresh Jeevanandam wrote:
> I got it:
> dict([k.split('=') for k in s.split(',')])
>
> Suresh Jeevanandam wrote:
>
>>Given a string
>>s = 'a=1,b=2'
>>
>>I want to create a dictionary {'a': '1', 'b': '2'}
>>
>>I did,
>>
>>dict(map(lambda k: k.split('='), s.split(',')))
>>
>>Is it possible to get r
I got it:
dict([k.split('=') for k in s.split(',')])
regards,
Suresh
Suresh Jeevanandam wrote:
> Given a string
> s = 'a=1,b=2'
>
> I want to create a dictionary {'a': '1', 'b': '2'}
>
> I did,
>
> dict(map(lambda k: k.split('='), s.split(',')))
>
> Is it possible to get rid of the lambda here
Given a string
s = 'a=1,b=2'
I want to create a dictionary {'a': '1', 'b': '2'}
I did,
dict(map(lambda k: k.split('='), s.split(',')))
Is it possible to get rid of the lambda here, without having to define
another function just for this.
Is this the easiest/straight-forward way to do this?
r
