On 2020-02-03 10:39 AM, Peter Otten wrote:
Frank Millman wrote:
This is a minor issue, and I have found an ugly workaround, but I
thought I would mention it.
Like this?
children = list(xml)
for y in children:
print(etree.tostring(y))
if y.get('z') == 'c':
child = etree.Ele
Frank Millman wrote:
> Hi all
>
> I usually send lxml queries to the lxml mailing list, but it appears to
> be not working, so I thought I would try here.
>
> This is a minor issue, and I have found an ugly workaround, but I
> thought I would mention it.
Like this?
children = list(xml)
for y i
Hi all
I usually send lxml queries to the lxml mailing list, but it appears to
be not working, so I thought I would try here.
This is a minor issue, and I have found an ugly workaround, but I
thought I would mention it.
In Python I can iterate through a list, and on a certain condition
app
