On Wed, Aug 4, 2010 at 9:38 PM, loial wrote:
> I have also been trying to get the return code and standard error.
p = Popen("..., stderr=PIPE)
Look up the docs for subprocess.Popen
cheers
James
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-- James Mills
--
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Thanks...that worked.
I have also been trying to get the return code and standard error.
How do I access these?
#!/usr/bin/python
import os
import subprocess
process=subprocess.Popen(['lpr', '-P' ,'raserlpr','/etc/hosts'],
shell=False, stdout=subprocess.PIPE, stderr=subprocess.PIPE)
print proce
loial wrote:
> I am am trying to run the following command via subprocess
>
> lpr -P printqueue filetoprint
>
> I cannot seem to get it to work and return stderr
>
> I think the issue is how to specify the arguments
>
> I am trying
>
> subprocess.Popen(['lpr -P' ,'laserlpr','/etc/hosts'], she
I am am trying to run the following command via subprocess
lpr -P printqueue filetoprint
I cannot seem to get it to work and return stderr
I think the issue is how to specify the arguments
I am trying
subprocess.Popen(['lpr -P' ,'laserlpr','/etc/hosts'], shell=False)
but get error :
Tracebac
