Thanks , and it has to be re.match()
On Thu, Sep 22, 2016 at 12:18 AM, MRAB wrote:
> On 2016-09-21 19:35, Ganesh Pal wrote:
>
>> Thanks Steve for the clues , quickly tried out # Version 1 doesn't seen
>> to work.
>>
>>
>> for line in hostname:
>
... regex = r'(.*) is array with i
On 2016-09-21 19:35, Ganesh Pal wrote:
Thanks Steve for the clues , quickly tried out # Version 1 doesn't seen
to work.
for line in hostname:
... regex = r'(.*) is array with id {}'.format(devid)
... mo = re.search(regex, line)
... print line, regex, mo
... if mo is not None
Thanks Steve for the clues , quickly tried out # Version 1 doesn't seen
to work.
>>> for line in hostname:
... regex = r'(.*) is array with id {}'.format(devid)
... mo = re.search(regex, line)
... print line, regex, mo
... if mo is not None:
... print mo.group(1)
...
RX-
On Wed, 21 Sep 2016 04:04 am, Ganesh Pal wrote:
> I am on python 2.7 and Linux
>
> I have the stdout in the below form , I need to write a function to get
> hostname for the given id.
>
>
> Example:
>
stdout
> 'hostname-1 is array with id 1\nhostname-2 is array with id 2\nhostname-3
> is
On Wed, Sep 21, 2016 at 4:04 AM, Ganesh Pal wrote:
> 1. store it in list and grep for id and return
> 2. store it in dict as key and value i.e hostname = { 'hostname1': 1} and
> return key
> 3. any other simple options.
4. Store it in dict, but the other way around. The key should be the
thing yo
On Wednesday, September 21, 2016 at 6:05:41 AM UTC+12, Ganesh Pal wrote:
> I am on python 2.7 ...
Why?
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I am on python 2.7 and Linux
I have the stdout in the below form , I need to write a function to get
hostname for the given id.
Example:
>>> stdout
'hostname-1 is array with id 1\nhostname-2 is array with id 2\nhostname-3
is array with id 3\n'
def get_hostname(id)
return id
what's a
On 24 mai, 19:21, "Christopher Anderson" <[EMAIL PROTECTED]>
wrote:
> > d=dict(a=1, b=2, c=3)
> > for k, v in d.iteritems():
> > d[k]=d[k]+1
>
> You might as well do: d[k] = v + 1, like for the list.
ops, yes it was a typo
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> d=dict(a=1, b=2, c=3)
> for k, v in d.iteritems():
> d[k]=d[k]+1
You might as well do: d[k] = v + 1, like for the list.
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Hello
I just want to update the data inside List or Dictionary without
adding or deleting object.
is this correct ?
l=[1, 2, 3]
for i, v in enumerate(l):
l[i]=v+1
d=dict(a=1, b=2, c=3)
for k, v in d.iteritems():
d[k]=d[k]+1
Both works, but :
are they correct ?
are they optimum for
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