Hi,
well i am able to find a loop in a list using two iterators.One
iterator runs "two times faster than the other", and if he encounters
the first, it means that there is a loop.
Example :
1,2,3,4,5,6,7,8,9,5
the algorithm would generate:
start - 1,2
iteration 1- 2, 4
iteration 2- 3, 6
iteratio
David Hláčik wrote:
> Hi,
>
> so okay, i will create a helping set, where i will be adding elements
> ID, when element ID will be allready in my helping set i will stop and
> count number of elements in helping set. This is how long my cycled
> linked list is.
> But what if i have another condi
Terry Reedy wrote:
David Hláčik wrote:
But what if i have another condition , and that is *i can use only
helping memory with constant size* ? This means i am not able to
create any set and adding elements there. I need to have a constant
size variables . This is complication a complication for
David Hláčik wrote:
so okay, i will create a helping set, where i will be adding elements
ID, when element ID will be allready in my helping set i will stop and
count number of elements in helping set. This is how long my cycled
linked list is.
CPython now does this in printing and marshalling
Hi,
so okay, i will create a helping set, where i will be adding elements
ID, when element ID will be allready in my helping set i will stop and
count number of elements in helping set. This is how long my cycled
linked list is.
But what if i have another condition , and that is *i can use only
h
David Hláčik wrote:
> dictionary with cycle structure
>
> Hello guys,
>
> I have a linked list where *number of elements is unlimited* and
> **last element points on random (can be first, last, in middle ,
> anywhere) element within linked list** - this is important . My goals
> is to create an
dictionary with cycle structure
Hello guys,
I have a linked list where *number of elements is unlimited* and
**last element points on random (can be first, last, in middle ,
anywhere) element within linked list** - this is important . My goals
is to create an architecture /scheme for **algoritmus