On 05/13/2010 12:51 PM, a wrote:
If your two arrays are of the same length, you can do things like
a = [2,3,3,4,5,6]
b = ['a', 'b', 'c', 'd', 'e', 'f']
print [m for (n,m) in zip(a,b) if n == 3]
and skip the indexes altogether.
mmm, that's clever, thanks. although i don't know wh
On 13 May, 18:18, Tim Chase wrote:
> On 05/13/2010 10:45 AM, a wrote:
>
>
>
>
>
> >>> a=[2,3,3,4,5,6]
>
> >>> i want to know the indices where a==3 (ie 1 and 2)
>
> >> indexes = [i for (i, v) in enumerate(a) where v==3]
>
> >>> then i want to reference these in a
>
> >> In a _what_? You can then
On 13 May, 17:41, Carey Tilden wrote:
> On Thu, May 13, 2010 at 8:45 AM, a
> wrote:
> > On 13 May, 16:19, Tim Chase wrote:
> >> On 05/13/2010 09:36 AM, a wrote:
>
> >> > this must be easy but its taken me a couple of hours already
>
> >> > i have
>
> >> > a=[2,3,3,4,5,6]
>
> >> > i want to know
On 05/13/2010 10:45 AM, a wrote:
a=[2,3,3,4,5,6]
i want to know the indices where a==3 (ie 1 and 2)
indexes = [i for (i, v) in enumerate(a) where v==3]
then i want to reference these in a
In a _what_? You can then do things like
for i in indexes:
print a[i]
(but you already
On Thu, May 13, 2010 at 8:45 AM, a wrote:
> On 13 May, 16:19, Tim Chase wrote:
>> On 05/13/2010 09:36 AM, a wrote:
>>
>> > this must be easy but its taken me a couple of hours already
>>
>> > i have
>>
>> > a=[2,3,3,4,5,6]
>>
>> > i want to know the indices where a==3 (ie 1 and 2)
>>
>> indexes =
On 13 May, 16:19, Tim Chase wrote:
> On 05/13/2010 09:36 AM, a wrote:
>
> > this must be easy but its taken me a couple of hours already
>
> > i have
>
> > a=[2,3,3,4,5,6]
>
> > i want to know the indices where a==3 (ie 1 and 2)
>
> indexes = [i for (i, v) in enumerate(a) where v==3]
>
> > then i
On 13 May, 15:47, Stefan Behnel wrote:
> a, 13.05.2010 16:36:
>
> > this must be easy but its taken me a couple of hours already
>
> > i have
>
> > a=[2,3,3,4,5,6]
>
> > i want to know the indices where a==3 (ie 1 and 2)
>
> indices = [ i for i,item in enumerate(a) if item == 3 ]
>
> > then i w
On 05/13/2010 09:36 AM, a wrote:
this must be easy but its taken me a couple of hours already
i have
a=[2,3,3,4,5,6]
i want to know the indices where a==3 (ie 1 and 2)
indexes = [i for (i, v) in enumerate(a) where v==3]
then i want to reference these in a
In a _what_? You can then do th
On 2010-05-13, Stefan Behnel wrote:
> a, 13.05.2010 16:36:
>> this must be easy but its taken me a couple of hours already
>>
>> i have
>>
>> a=[2,3,3,4,5,6]
>>
>> i want to know the indices where a==3 (ie 1 and 2)
>
>indices = [ i for i,item in enumerate(a) if item == 3 ]
That form of list c
On 2010-05-13, a wrote:
> this must be easy but its taken me a couple of hours already
>
> i have
>
> a=[2,3,3,4,5,6]
>
> i want to know the indices where a==3 (ie 1 and 2)
>
> then i want to reference these in a
>
> ie what i would do in IDL is
>
> b=where(a eq 3)
> a1=a(b)
>
> any ideas?
For a
On Thu 13 May 2010 10:36:58 AM EDT, a wrote:
> this must be easy but its taken me a couple of hours already
>
> i have
>
> a=[2,3,3,4,5,6]
>
> i want to know the indices where a==3 (ie 1 and 2)
>
> then i want to reference these in a
>
> ie what i would do in IDL is
>
> b=where(a eq 3)
> a1=a(b)
a, 13.05.2010 16:36:
this must be easy but its taken me a couple of hours already
i have
a=[2,3,3,4,5,6]
i want to know the indices where a==3 (ie 1 and 2)
indices = [ i for i,item in enumerate(a) if item == 3 ]
then i want to reference these in a
print [ a[i] for i in indices ]
St
this must be easy but its taken me a couple of hours already
i have
a=[2,3,3,4,5,6]
i want to know the indices where a==3 (ie 1 and 2)
then i want to reference these in a
ie what i would do in IDL is
b=where(a eq 3)
a1=a(b)
any ideas?
Thanks
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