This is nearly the same question you asked under another name
yesterday. Its not clear what you really want to do. You are asking
what the url is of the page you retrieve by providing the same url.
On Fri, Nov 1, 2013 at 7:33 AM, Alister wrote:
> On Thu, 31 Oct 2013 08:59:00 -0700, bhaktanishan
On Thu, 31 Oct 2013 08:59:00 -0700, bhaktanishant wrote:
> I want to extract the page-url. for example:
> if i have this code
>
> import urllib2 from bs4 import BeautifulSoup link =
> "http://www.google.com";
> page = urllib2.urlopen(link).read()
> soup = BeautifulSoup(page)
>
> then i can extra
On 31/10/2013 15:59, bhaktanish...@gmail.com wrote:
I want to extract the page-url. for example:
if i have this code
import urllib2
from bs4 import BeautifulSoup
link = "http://www.google.com";
page = urllib2.urlopen(link).read()
soup = BeautifulSoup(page)
then i can extract title of page by:
I want to extract the page-url. for example:
if i have this code
import urllib2
from bs4 import BeautifulSoup
link = "http://www.google.com";
page = urllib2.urlopen(link).read()
soup = BeautifulSoup(page)
then i can extract title of page by:
title = soup.title
but i want to know that how to ext