Hey
Thanks.
I just resolved it and yes you are right there was a (hidden) new-line to
it. I found it in a crude way of putting dots before and after. I was to
post about it here and saw your message.
I was not knowing about %r. Thanks for that. Thats a good addition to my
knowledge.
Thanks a bu
Hi Sagar,
In order to be able to help you I propose following:
On 09/15/2011 06:54 AM, Sagar Neve wrote:
. . .
> print "hello..Man_Param=%s,Opt_Param1=%s,
> Opt_Param2=%s\n" %(Man_Param,Opt_Param1,Opt_Param2)
Change above line into
> print "hello..Man_Par
Yes. It is been resolved now for the sample program. however, as mentioned
in other post. It is not working in the main program
On Thu, Sep 15, 2011 at 10:25 AM, Kushal Kumaran <
kushal.kumaran+pyt...@gmail.com> wrote:
> On Thu, Sep 15, 2011 at 10:11 AM, Sagar Neve wrote:
> > Here is the code
>
On Thu, Sep 15, 2011 at 2:55 PM, Kushal Kumaran
wrote:
> That looks like a bash error message. Syntax errors in python show up
> with a stack trace. Run your program using the python interpreter
> like this:
>
> python file.py
> OR
> python3 file.py
>
> whatever is applicable in your environment
On Thu, Sep 15, 2011 at 10:11 AM, Sagar Neve wrote:
> Here is the code
>
>
> url="http://xy.yz.com/us/r1000/012/Purple/b1/c6/e2/mzm.dxkjsfbl..d2.dpkg.ipa";
>
> Man_Param="/us/r1000"
> Opt_Param1="Purple"
> Opt_Param2="dpkg.ipa"
>
> if (Opt_Param2 in url):
> print "hello."
> else:
> print "
I figured it out with the sample program I gave you. It was my mistake;
However, the same thing with same values is not working in my main program.
Here is what I am trying: The program traverses with correct values upto the
if condition we just discussed; but fails to quality that if condition;
On Thu, Sep 15, 2011 at 2:41 PM, Sagar Neve wrote:
> ./sample.py: line 9: syntax error near unexpected token `:'
> ./sample.py: line 9: `if (Opt_Param2 in url): '
>
It worked for me in Python 3.2. What version of Python are you using?
ChrisA
--
http://mail.python.org/mailman/listinfo/python-
Here is the code
url="http://xy.yz.com/us/r1000/012/Purple/b1/c6/e2/mzm.dxkjsfbl..d2.dpkg.ipa
"
Man_Param="/us/r1000"
Opt_Param1="Purple"
Opt_Param2="dpkg.ipa"
if (Opt_Param2 in url):
print "hello."
else:
print "bye."
It gives me:
./sample.py: line 9: syntax error near unexpected tok
On Wed, Sep 14, 2011 at 8:33 PM, Sagar Neve wrote:
> If A in B:
> does nt seem to be working.
> Am I missing something here.
Please provide a snippet of the code in question, and be specific
about how it's not working.
Cheers,
Chris
--
http://rebertia.com
--
http://mail.python.org/mailman/listi
If A in B:
does nt seem to be working.
Am I missing something here.
-$agar
On Sep 15, 2011 7:25 AM, "Chris Rebert" wrote:
> On Wed, Sep 14, 2011 at 6:41 PM, Sagar Neve wrote:
>> Hi,
>> I have a small program where I want to do just a small regex operation.
>> I want to see if value of a variable
On Wed, Sep 14, 2011 at 6:41 PM, Sagar Neve wrote:
> Hi,
> I have a small program where I want to do just a small regex operation.
> I want to see if value of a variable 'A' is present in an another variable
> 'B'. The below code works fine but as soon as the variable 'A' has some
> string includ
Hi,
I have a small program where I want to do just a small regex operation.
I want to see if value of a variable 'A' is present in an another variable
'B'. The below code works fine but as soon as the variable 'A' has some
string including a dot it fails.
for example say:
B="dpkg.ipaz
Hi,
I have a small program where I want to do just a small regex operation.
I want to see if value of a variable 'A' is present in an another variable
'B'. The below code works fine but as soon as the variable 'A' has some
string including a dot it fails.
for example say:
B="dpkg.ipaz
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