>
> print sorted (dates, key=lambda x: abs (x-one_date))[0]
>
>
>
>
> TJG
> --
> http://mail.python.org/mailman/listinfo/python-list
>
>
--
View this message in context:
http://www.nabble.com/find-nearest-time-in-datetime-list-tp15180398p15183205.html
Sent f
Boris Borcic wrote:
> min(DTlist,key=lambda date : abs(dt-date))
In Python2.4:
Traceback (most recent call last):
File "", line 1, in ?
TypeError: min() takes no keyword arguments
Looks like min() only started taking keywords (key) from
Python2.5 forward.
But the min() solution is g
washakie wrote:
> Hello,
>
> I have a list of datetime objects: DTlist, I have another single datetime
> object: dt, ... I need to find the nearest DTlist[i] to the dt is
> there a simple way to do this? There isn't necessarily an exact match...
>
> Thanks!
> .john
>
min(DTlist,key=lambd
> I have a list of datetime objects: DTlist, I have another single datetime
> object: dt, ... I need to find the nearest DTlist[i] to the dt is
> there a simple way to do this? There isn't necessarily an exact match...
import datetime
dates = [datetime.datetime(2007,m, 1) for m in range(1,1
washakie wrote:
> Hello,
>
> I have a list of datetime objects: DTlist, I have another single datetime
> object: dt, ... I need to find the nearest DTlist[i] to the dt is
> there a simple way to do this? There isn't necessarily an exact match...
import datetime
dates = [datetime.date (20
http://www.nabble.com/find-nearest-time-in-datetime-list-tp15180398p15180398.html
Sent from the Python - python-list mailing list archive at Nabble.com.
--
http://mail.python.org/mailman/listinfo/python-list
