Jason wrote:
> I believe what you are trying to do is something like the following.
>
> [code]
> def isIntLike(x):
> try:int(x)
> except: return False
*Never* ever use a bare except clause. *Always* specify wich exceptions
you are expecting. (NB : here, TypeError and ValueError).
In article <[EMAIL PROTECTED]>,
Alex Pavluck <[EMAIL PROTECTED]> wrote:
>Hello. I get the following error with the following code. Is there
>something wrong with my Python installation?
>
>code:
>import types
>something = input("Enter something and I will tell you the type: ")
>
>if type(something
I believe what you are trying to do is something like the following.
[code]
def isIntLike(x):
try:int(x)
except: return False
else: return True
something = raw_input("Enter something and I will tell you the type: ")
if isIntLike(something):print "I am an int
Alex Pavluck wrote:
> Hello. I get the following error with the following code. Is there
> something wrong with my Python installation?
>
> code:
> import types
> something = input("Enter something and I will tell you the type: ")
>
> if type(something) is types.IntType:
> print "you entered
Alex Pavluck wrote:
> String: Source for exec/eval is unavailable
I'm not able to find this message anywhere in the Python-2.4.3 sources.
What python version are you using? What input did you enter when the
prompt appeared? and copy&paste the *exact* exception you got including
the full traceback.
Hello. I get the following error with the following code. Is there
something wrong with my Python installation?
code:
import types
something = input("Enter something and I will tell you the type: ")
if type(something) is types.IntType:
print "you entered an integer"
elif type(something) is t
