On Wed, 01 Apr 2009 19:13:33 +0200, TP wrote:
> Hi everybody,
>
> Try the following python statements:
>
"%.40f" % 0.222
> '0.098864108374982606619596'
float( 0.222)
> 0.1
Remove the leading quote
TP wrote:
> Hi everybody,
>
> Try the following python statements:
>
> >>> "%.40f" % 0.222
> '0.098864108374982606619596'
> >>> float( 0.222)
> 0.1
>
> It seems the first result is the same than the fol
It's not at all clear what you really want. You say you want to "use"
the %e format, but then imply you're then going to turn it back into a
float. Since I don't know what the end goal is, I'll just comment
generally.
All Python floating point is equivalent to the 'double' type of the C
imp
On Apr 1, 12:13 pm, TP wrote:
> Hi everybody,
>
> Try the following python statements:
>
> >>> "%.40f" % 0.222
>
> '0.098864108374982606619596'>>> float(
> 0.222)
>
> 0.1
>
> It seems the first result is the s
Hi everybody,
Try the following python statements:
>>> "%.40f" % 0.222
'0.098864108374982606619596'
>>> float( 0.222)
0.1
It seems the first result is the same than the following C program:
#
