Fredrik, thanks for your posting. I really appretiate your reply and
your way how you kindly answer even stupid newbie's questions on this
mailing list.
I was trying: int("0xf") but I did not have idea about the optional
"base" parameter for the int function.
Thanks a lot.
Petr
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http://mail.py
Petr Jakes wrote:
> I am trying to convert string to the "escaped string".
> example: from "0xf" I need "\0xf"
> I am able to do it like:
>
> a="0xf"
> escaped_a=("\%s" % a ).decode("string_escape")
>
> Bu
small mistake in my previous posting, sorry
from "0xf" I need "\xf" of course
and mentioned code gives me "\0xf" of course.
Thanks for your postings
Petr Jakes
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http://mail.python.org/mailman/listinfo/python-list
Hi,
I am trying to convert string to the "escaped string".
example: from "0xf" I need "\0xf"
I am able to do it like:
a="0xf"
escaped_a=("\%s" % a ).decode("string_escape")
But it looks a little bit complicated in this
