On 29 ene, 22:47, Zbigniew Braniecki <[EMAIL PROTECTED]>
wrote:
> The new one is of course much better and cleaner (the old one is
> bloated), but I'm wondering if there is a faster way to compare two
> lists and find out what was added, what was removed, what was changed.
> I can simply iterate t
[EMAIL PROTECTED] wrote:
> Zbigniew Braniecki:
>> Is there a way to speed it up? Any easier way? Faster method?
>
> This problem is a bit messy. Maybe it's better to sidestep the
> problem, and not use a list, and create an object that wraps the list,
> so it always keeps an updated record of what
Zbigniew Braniecki:
> Is there a way to speed it up? Any easier way? Faster method?
This problem is a bit messy. Maybe it's better to sidestep the
problem, and not use a list, and create an object that wraps the list,
so it always keeps an updated record of what changes are done... but
you have to
Hi all.
I'm working on a tool for localizers.
I have two Lists with Entities/Strings/Comments (each L10n file is built
of those three elements).
So I have sth like:
l10nObject = []
l10nObject.append(Comment('foo'))
l10nObject.append("string")
l10nObject.append(Entity('name', 'value'))
etc. I
