Re: class='something' as kwarg

2007-11-17 Thread George Sakkis
On Nov 17, 3:45 am, "Vladimir Rusinov" <[EMAIL PROTECTED]> wrote: > Hello! > > I'm using beautiful soup html parser, and I need to get all ' class=g>...' tags. > It can be done by: > > import BeautifulSoup as BSoup > > ... > > soup = BSoup(page) > for div in soup.findAll('div', class='g'): > >

Re: class='something' as kwarg

2007-11-17 Thread Marc Christiansen
Vladimir Rusinov <[EMAIL PROTECTED]> wrote: > I'm using beautiful soup html parser, and I need to get all ' class=g>...' tags. > It can be done by: > > import BeautifulSoup as BSoup from BeautifulSoup import BeautifulSoup as BSoup > > ... > > soup = BSoup(page) > for div in soup.findAll('div',

Re: class='something' as kwarg

2007-11-17 Thread Peter Otten
Vladimir Rusinov wrote: > I'm using beautiful soup html parser, and I need to get all ' class=g>...' tags. > It can be done by: > > import BeautifulSoup as BSoup > > ... > > soup = BSoup(page) > for div in soup.findAll('div', class='g'): > > > But how can I use `class` as kwarg name? # h

Re: class='something' as kwarg

2007-11-17 Thread GuillaumeC
> But how can I use `class` as kwarg name? soup.findAll('div', **{'class':'g'}) -- http://mail.python.org/mailman/listinfo/python-list

class='something' as kwarg

2007-11-17 Thread Vladimir Rusinov
Hello! I'm using beautiful soup html parser, and I need to get all '...' tags. It can be done by: import BeautifulSoup as BSoup ... soup = BSoup(page) for div in soup.findAll('div', class='g'): But how can I use `class` as kwarg name? -- Vladimir Rusinov GreenMice Solutions: IT-решения