Re: __prepare__ metaclass's method

2016-10-28 Thread ast
"Peter Otten" <__pete...@web.de> a écrit dans le message de news:mailman.34.1477663877.31204.python-l...@python.org... ast wrote: class T(type): ... def __new__(*args, **kw): return type.__new__(*args) ... def __prepare__(*args, **kw): ... print(kw) ... return {} ...

Re: __prepare__ metaclass's method

2016-10-28 Thread Peter Otten
ast wrote: > Hi > > On python doc here: > > https://docs.python.org/3.4/reference/datamodel.html > > it is said about __prepare__ metaclass's method: > > If the metaclass has a __prepare__ attribute, it is called as > namespace = metaclass.__prepare

__prepare__ metaclass's method

2016-10-28 Thread ast
Hi On python doc here: https://docs.python.org/3.4/reference/datamodel.html it is said about __prepare__ metaclass's method: If the metaclass has a __prepare__ attribute, it is called as namespace = metaclass.__prepare__(name, bases, **kwds) where the additional keyword arguments, i