On Wed, May 20, 2015 at 2:39 AM, Cecil Westerhof wrote:
> By the way, what also works is:
> p = None
>
> But it was just a try in ipython3. I would never do this in real code.
> I was just curious if this would be handled correctly and it is. :-)
That _may_ work, but it depends on their not b
Op Tuesday 19 May 2015 17:49 CEST schreef Ian Kelly:
> On Tue, May 19, 2015 at 8:44 AM, Cecil Westerhof wrote:
>> I looked at the documentation. Is it necessary to do a:
>> p.wait()
>> afterwards?
>
> It's good practice to clean up zombie processes by waiting on them,
> but they will also get cle
On Tue, May 19, 2015 at 8:44 AM, Cecil Westerhof wrote:
> I looked at the documentation. Is it necessary to do a:
> p.wait()
> afterwards?
It's good practice to clean up zombie processes by waiting on them,
but they will also get cleaned up when your script exits.
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Op Tuesday 19 May 2015 15:16 CEST schreef Oscar Benjamin:
> On 19 May 2015 at 13:24, Cecil Westerhof wrote:
>> I have the following code:
>> from __future__ import division, print_function
>>
>> import subprocess
>>
>> p = subprocess.Popen('ls -l', shell = True, stdout =
>> subprocess.PIPE) f
Am 19.05.2015 um 15:16 schrieb Oscar Benjamin:
However the normal way to do this is to iterate over stdout directly:
Depends. There may be differences when it comes to buffering etc...
Thomas
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On 19 May 2015 at 13:24, Cecil Westerhof wrote:
> I have the following code:
> from __future__ import division, print_function
>
> import subprocess
>
> p = subprocess.Popen('ls -l', shell = True, stdout = subprocess.PIPE)
> for line in iter(p.stdout.readline, ''):
> pr
I have the following code:
from __future__ import division, print_function
import subprocess
p = subprocess.Popen('ls -l', shell = True, stdout = subprocess.PIPE)
for line in iter(p.stdout.readline, ''):
print(line.rstrip().decode('utf-8'))
p = subprocess.Popen('l
