On 10 September 2013 03:27, Jason Friedman wrote:
>>
>> OK, you're well inside the "finite" domain. Also, you probably want less
>> than the "natural" randomness. I'd probably shuffle the potential
>> quarterbacks and the others in independent lists, and then pick one half of
>> each to form a tea
Op 10-09-13 04:27, Jason Friedman schreef:
>>> I coach a flag football team of 11-year-olds. A stated goal of the
>>> league is that every player should get nearly equal playing time and
>>> that winning is of secondary importance. That said, some players just
>>> can't throw the ball at all, and
>> I coach a flag football team of 11-year-olds. A stated goal of the
>> league is that every player should get nearly equal playing time and
>> that winning is of secondary importance. That said, some players just
>> can't throw the ball at all, and having a quarterback who cannot throw
>> is no
Op 09-09-13 11:11, Steven D'Aprano schreef:
> On Mon, 09 Sep 2013 09:12:05 +0200, Antoon Pardon wrote:
>
>> Op 09-09-13 02:21, Dennis Lee Bieber schreef:
>>> On Sun, 08 Sep 2013 19:48:55 +0200, Antoon Pardon
>>> declaimed the following:
>>>
Op 08-09-13 04:12, Jason Friedman schreef:
> ch
Jason Friedman wrote:
[You may have sent this in private mail by accident, so I take the freedom
to bring this back to the mailing list]
> I'm realizing with your question
which was roughly: Do picks from a pool influence probability of subsequent
picks, i. e. weather the pool is finite or in
On Mon, 09 Sep 2013 09:12:05 +0200, Antoon Pardon wrote:
> Op 09-09-13 02:21, Dennis Lee Bieber schreef:
>> On Sun, 08 Sep 2013 19:48:55 +0200, Antoon Pardon
>> declaimed the following:
>>
>>> Op 08-09-13 04:12, Jason Friedman schreef:
choices = dict()
choices["apple"] = 10
choice
Op 09-09-13 02:21, Dennis Lee Bieber schreef:
> On Sun, 08 Sep 2013 19:48:55 +0200, Antoon Pardon
> declaimed the following:
>
>> Op 08-09-13 04:12, Jason Friedman schreef:
>>> choices = dict()
>>> choices["apple"] = 10
>>> choices["pear"] = 20
>>> choices["banana"] = 15
>>> choices["orange"] = 2
On 08Sep2013 20:21, Dennis Lee Bieber wrote:
| However, I would not use a dictionary for this. An ordered list should
| work better... for small samples a list containing repeats (by weight) of
| each choice, and then use a random integer whose range is 0..len(list)-1
| would suffice.
|
| c
Op 08-09-13 04:12, Jason Friedman schreef:
choices = dict()
choices["apple"] = 10
choices["pear"] = 20
choices["banana"] = 15
choices["orange"] = 25
choices["kiwi"] = 30
I want to pick sets of fruit, three in a set, where the chance of
selecting a given fruit is proportional to its weight. In t
Jason Friedman wrote:
> choices = dict()
> choices["apple"] = 10
> choices["pear"] = 20
> choices["banana"] = 15
> choices["orange"] = 25
> choices["kiwi"] = 30
>
> I want to pick sets of fruit, three in a set, where the chance of
> selecting a given fruit is proportional to its weight. In the e
choices = dict()
choices["apple"] = 10
choices["pear"] = 20
choices["banana"] = 15
choices["orange"] = 25
choices["kiwi"] = 30
I want to pick sets of fruit, three in a set, where the chance of
selecting a given fruit is proportional to its weight. In the example
above, pears should appear twice a
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