Am 09.01.2012 03:21, schrieb Steven D'Aprano:
> What am I doing wrong?
You aren't doing anything wrong. It's just not possible to have
something different than a dict as a type's __dict__. It's a deliberate
limitation and required optimization. The __prepare__ hook allows to you
have a dict subcla
I'm using Python 3.1 and trying to create a class using an OrderedDict as
its __dict__, but it isn't working as I expect.
See http://www.python.org/dev/peps/pep-3115/ for further details.
Here is my code:
from collections import OrderedDict
# The metaclass
class OrderedClass(type):
#
