On 09/15/2010 10:48 AM, Peter Otten wrote:
I personally would not be too concerned about the leading underscore, but
you can use
string.Formatter().parse(template)
instead.
Thanks for this pointer. I like it this way. So if I now combine your
generator with your suggestion, I end up with som
Andre Alexander Bell wrote:
> On 09/15/2010 10:00 AM, Peter Otten wrote:
>> def extract_names(t, recurse=1):
>> for _, name, fmt, _ in t._formatter_parser():
>> if name is not None:
>> yield name
>> if recurse and fmt is not None:
>> for name in ext
On 09/15/2010 10:00 AM, Peter Otten wrote:
def extract_names(t, recurse=1):
for _, name, fmt, _ in t._formatter_parser():
if name is not None:
yield name
if recurse and fmt is not None:
for name in extract_names(fmt, recurse-1):
yi
Peter Otten wrote:
> Andre Alexander Bell wrote:
>
>> On 09/14/2010 08:20 PM, Miki wrote:
>>> You can use ** syntax:
>> english = {'hello':'hello'}
>> s.format(**english)
>>
>> Thanks for your answer. Actually your answer tells me that my example
>> was misleading. Consider the template
Andre Alexander Bell wrote:
> On 09/14/2010 08:20 PM, Miki wrote:
>> You can use ** syntax:
> english = {'hello':'hello'}
> s.format(**english)
>
> Thanks for your answer. Actually your answer tells me that my example
> was misleading. Consider the template
>
> s = 'A template with {vari
On 09/14/2010 08:20 PM, Miki wrote:
You can use ** syntax:
english = {'hello':'hello'}
s.format(**english)
Thanks for your answer. Actually your answer tells me that my example
was misleading. Consider the template
s = 'A template with {variable1} and {variable2} placeholders.'
I'm seeking
On Tue, Sep 14, 2010 at 3:20 PM, Thomas Jollans wrote:
> On Tuesday 14 September 2010, it occurred to Miki to exclaim:
>> You can use ** syntax:
>> >>> english = {'hello':'hello'}
>> >>> s.format(**english)
>
> No, you can't. This only works with dicts, not with arbitrary mappings, or
> dict subcl
On Tuesday 14 September 2010, it occurred to Miki to exclaim:
> You can use ** syntax:
> >>> english = {'hello':'hello'}
> >>> s.format(**english)
No, you can't. This only works with dicts, not with arbitrary mappings, or
dict subclasses that try to do some kind of funny stuff.
>
> On Sep 14,
You can use ** syntax:
>>> english = {'hello':'hello'}
>>> s.format(**english)
On Sep 14, 9:59 am, Andre Alexander Bell wrote:
> Hello,
>
> I'm used to write in Python something like
>
> >>> s = 'some text that says: %(hello)s'
>
> and then have a dictionary like
>
> >>> english = { 'hello': 'h
Hello,
I'm used to write in Python something like
>>> s = 'some text that says: %(hello)s'
and then have a dictionary like
>>> english = { 'hello': 'hello' }
and get the formatted output like this:
>>> s % english
Occasionally I want to extract the field names from the template string.
I w
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