On Jul 28, 11:36 pm, Andrew Savige <[EMAIL PROTECTED]> wrote:
(snipped)
>
> Yes. Here's a simpler example without any backreferences:
>
> s = re.split(r'(?<=\d)(?=\D)', '1B2D3')
>
> That works in Perl but not in Python.
> Is it that "chaining" assertions together like this is not supported in Pyt
--- "[EMAIL PROTECTED]" <[EMAIL PROTECTED]> wrote:
> Using itertools:
>
> import itertools
>
> s = 'ABBBCC'
> print [''.join(grp) for key, grp in itertools.groupby(s)]
Nice.
> Using re:
>
> import re
>
> pat = re.compile(r'((\w)\2*)')
> print [t[0] for t in re.findall(pat, s)]
Also nice. Esp
On Jul 28, 9:46 pm, Andrew Savige <[EMAIL PROTECTED]> wrote:
> Python beginner here.
>
> For a string 'ABBBCC', I want to produce a list ['A', 'BBB', 'CC'].
> That is, break the string into pieces based on change of character.
> What's the best way to do this in Python?
>
> Using Python 2.5.1, I tr
Python beginner here.
For a string 'ABBBCC', I want to produce a list ['A', 'BBB', 'CC'].
That is, break the string into pieces based on change of character.
What's the best way to do this in Python?
Using Python 2.5.1, I tried:
import re
s = re.split(r'(?<=(.))(?!\1)', 'ABBBCC')
for e in s: pri
