ermanolillo writes:
> HOST is send by the keyboard. It´s the IPv6 address of my interface eth0.
> For example, FE80::0202:B3FF:FE1E:8329.
This is a link-local address, you can't use it just like that (you may
have several interfaces with the same link-local addr). Use getaddrinfo
on "FE80...%et
On Fri, Jan 23, 2015 at 2:24 AM, ermanolillo wrote:
> HOST is send by the keyboard. It´s the IPv6 address of my interface eth0.
> For example, FE80::0202:B3FF:FE1E:8329.
I can't duplicate the problem. Are you certain that this is indeed an
appropriate address?
ChrisA
--
https://mail.python.org
HOST is send by the keyboard. It´s the IPv6 address of my interface eth0.
For example, FE80::0202:B3FF:FE1E:8329.
Thanks
--
View this message in context:
http://python.6.x6.nabble.com/Socket-ICMP-V6-error-tp5083962p5083982.html
Sent from the Python - python-list mailing list archive at
On Thu, Jan 22, 2015 at 7:00 PM, ermanolillo wrote:
> s = socket.socket(socket.AF_INET6, socket.SOCK_RAW, socket.IPPROTO_ICMPV6)
>
> However I recive the next error:
>
>
>
> File "server.py", line 16, in
> s.bind((HOST, 0))
> File "/usr/lib/python2.7/socket.py", line 224, in meth
> return getattr
File "/usr/lib/python2.7/socket.py", line 224, in meth
return getattr(self._sock,name)(*args)
socket.error: [Errno 22] Invalid argument
Could someone please help me?.
Thanks in advance
--
View this message in context:
http://python.6.x6.nabble.com/Socket-ICMP-V6-error-tp5083962.html
