Steve Holden wrote:
John Roth wrote:
What happens with the second operand is a bit of
sleight of hand. The object returned from super()
gives you access to the methods on the next level up the
mro, however when you use it to invoke a method,
then the 'self' passed to that method is the second
objec
Steve Holden wrote:
John Roth wrote:
"Tobiah" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
What is the purpose of the second argument to super()?
I've always found the docs to be fairly confusing.
They didn't give me enough context to tell what
was
John Roth wrote:
"Tobiah" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
What is the purpose of the second argument to super()?
I've always found the docs to be fairly confusing.
They didn't give me enough context to tell what
was going on. I also find
"Tobiah" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
What is the purpose of the second argument to super()?
I've always found the docs to be fairly confusing.
They didn't give me enough context to tell what
was going on. I also find the terminology confu
Tobiah wrote:
What is the purpose of the second argument to super()?
You probably want to check the docs[1] again. They give an example:
class C(B):
def meth(self, arg):
super(C, self).meth(arg)
What is meant by the returning of an 'unbound' object
when the argument is omitt
What is the purpose of the second argument to super()?
What is meant by the returning of an 'unbound' object
when the argument is omitted.
Also, when would I pass an object as the second argument,
and when would I pass a type?
Thanks,
Tobiah
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