Re: Search or compai problem

2006-08-21 Thread Gabriel Genellina
At Saturday 19/8/2006 23:43, [EMAIL PROTECTED] wrote: > >it is really lstusers (it is an L not a # 1), Some of the output from > >print lstUsers has the output of None. I and trying to filter the None > >out of the list. I come from a perl background and this is how I do > >thing in perl > >

Re: Search or compai problem

2006-08-19 Thread timgerr
Gabriel Genellina wrote: > At Saturday 19/8/2006 01:16, [EMAIL PROTECTED] wrote: > > >it is really lstusers (it is an L not a # 1), Some of the output from > >print lstUsers has the output of None. I and trying to filter the None > >out of the list. I come from a perl background and this is ho

Re: Search or compai problem

2006-08-18 Thread Gabriel Genellina
At Saturday 19/8/2006 01:16, [EMAIL PROTECTED] wrote: it is really lstusers (it is an L not a # 1), Some of the output from print lstUsers has the output of None. I and trying to filter the None out of the list. I come from a perl background and this is how I do thing in perl None is a uni

Re: Search or compai problem

2006-08-18 Thread timgerr
John Machin wrote: > Gallagher, Tim (NE) wrote: > > I am new to python and I want to compare 2 strings, here is my code: > > [start] > > > > import active_directory > > import re > > > > lstUsers = [] > > Using "lst" or "l" as a variable name is bad news in any language; with > many fonts they are

Re: Search or compai problem

2006-08-18 Thread John Machin
Gallagher, Tim (NE) wrote: > I am new to python and I want to compare 2 strings, here is my code: > [start] > > import active_directory > import re > > lstUsers = [] Using "lst" or "l" as a variable name is bad news in any language; with many fonts they are too easily misread as "1st" or "1" respe

Search or compai problem

2006-08-18 Thread Gallagher, Tim (NE)
I am new to python and I want to compare 2 strings, here is my code: [start] import active_directory import re lstUsers = [] users = active_directory.root() for user in users.search ("sn='gallagher'"): lstUsers.append(user.samAccountName) print "--