TYR a écrit :
> On Oct 29, 11:51 am, Duncan Booth <[EMAIL PROTECTED]>
> wrote:
>
>>TYR <[EMAIL PROTECTED]> wrote:
>>
>>>To do anything with it, you then need to create a cursor object by
>>>calling foo's method cursor (bar = foo.cursor).
>>
>>Perhaps this would work better if you actually try call
TYR a écrit :
> Has anyone else experienced a weird SQLite3 problem?
>
> Going by the documentation at docs.python.org, the syntax is as
> follows:
> foo = sqlite3.connect(dbname) creates a connection object representing
> the state of dbname and assigns it to variable foo. If dbname doesn't
> exi
On Oct 29, 11:51 am, Duncan Booth <[EMAIL PROTECTED]>
wrote:
> TYR <[EMAIL PROTECTED]> wrote:
> > To do anything with it, you then need to create a cursor object by
> > calling foo's method cursor (bar = foo.cursor).
>
> Perhaps this would work better if you actually try calling foo's method?
>
>
TYR <[EMAIL PROTECTED]> wrote:
> To do anything with it, you then need to create a cursor object by
> calling foo's method cursor (bar = foo.cursor).
Perhaps this would work better if you actually try calling foo's method?
bar = foo.cursor()
Without the parentheses all you are doing is
TYR wrote:
> Has anyone else experienced a weird SQLite3 problem?
>
> Going by the documentation at docs.python.org, the syntax is as
> follows:
> foo = sqlite3.connect(dbname) creates a connection object representing
> the state of dbname and assigns it to variable foo. If dbname doesn't
> exist
Has anyone else experienced a weird SQLite3 problem?
Going by the documentation at docs.python.org, the syntax is as
follows:
foo = sqlite3.connect(dbname) creates a connection object representing
the state of dbname and assigns it to variable foo. If dbname doesn't
exist, a file of that name is c
