I extracted an isolated problem from a slightly more complex
situation, that's why I'm using REs.
Thank you all for your help, my problem is now solved.
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André writes:
> How about the following:
>
> >>> s = 'a=b,c=d'
> >>> t = []
> >>> for u in s.split(','):
> ... t.extend(u.split('='))
s = 'a = b = c, d = e'
=> ['a ', ' b ', ' c', ' d ', ' e']
Ugh.
-- [mdw]
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Ciccio writes:
> suppose I have:
>
> s='a=b, c=d'
>
> and I want to extract sub-strings a,b,c and d from s (and in general
> from any longer list of such comma separated pairs).
[...]
> In [12]: re.findall(r'(.+)=(.+)', s)
> Out[12]: [('a=b, c', 'd')]
I think there are two logically separate job
2010/12/22 Ciccio :
> Hi all,
> suppose I have:
>
> s='a=b, c=d'
>
> and I want to extract sub-strings a,b,c and d from s (and in general from
> any longer list of such comma separated pairs).
> Some failed attempts:
>
> In [12]: re.findall(r'(.+)=(.+)', s)
> Out[12]: [('a=b, c', 'd')]
>
> [...]
>
On Wednesday, December 22, 2010 12:22:22 PM UTC-4, Francesco Napolitano wrote:
> Hi all,
> suppose I have:
>
> s='a=b, c=d'
>
> and I want to extract sub-strings a,b,c and d from s (and in general
> from any longer list of such comma separated pairs).
> Some failed attempts:
>
> In [12]: re.fin
Hi all,
suppose I have:
s='a=b, c=d'
and I want to extract sub-strings a,b,c and d from s (and in general
from any longer list of such comma separated pairs).
Some failed attempts:
In [12]: re.findall(r'(.+)=(.+)', s)
Out[12]: [('a=b, c', 'd')]
In [13]: re.findall(r'(.+?)=(.+)', s)
Out[13]:
