On 25Oct2010 01:37, Stefan Schwarzer wrote:
| From the question and the code snippet the OP gave I assumed
| he meant that there already was a sequence (i. e. linear
| structure) to begin with.
I suspected that was your interpretation.
| By the way, I think a well-known example of what you
| des
Hi Cameron,
On 2010-10-25 01:08, Cameron Simpson wrote:
> On 24Oct2010 20:58, Stefan Schwarzer wrote:
> | On 2010-10-21 00:27, Sebastian wrote:
> | > Is there a simpler way to yield all elements of a sequence than this?
> | > for x in xs:
> | > yield x
> |
> | Can you give an example where y
On 24Oct2010 20:58, Stefan Schwarzer wrote:
| On 2010-10-21 00:27, Sebastian wrote:
| > Is there a simpler way to yield all elements of a sequence than this?
| > for x in xs:
| > yield x
|
| Can you give an example where you would need this? Can't
| you just iterate over the sequence?
The us
Hi Sebastian,
On 2010-10-21 00:27, Sebastian wrote:
> Is there a simpler way to yield all elements of a sequence than this?
> for x in xs:
> yield x
Can you give an example where you would need this? Can't
you just iterate over the sequence? If you really need an
iterator, you can use `iter(s
On Wed, Oct 20, 2010 at 3:27 PM, Sebastian
wrote:
> Hi,
> Is there a simpler way to yield all elements of a sequence than this?
> for x in xs:
> yield x
Not presently. There's a related PEP under discussion though:
PEP 380: Syntax for Delegating to a Subgenerator
http://www.python.org/dev/peps
