On Mon, Apr 21, 2014 at 11:21 PM, Ivan Ivanivich wrote:
> if "basis" is 15, then "mod" == 0 twice - when the "divider" is 3 and 15
Good! Yes, you worked out exactly what the problem is. :)
There are ways to simplify your code, but it's now giving the correct
result, so that's the most important
On 2014-04-21 06:21, Ivan Ivanivich wrote:
> > Find the sum of all the multiples of 3 or 5 below 1000.
> my new version of script:
>
> total = 0
> div1 = 3
> div2 = 5
> for basis in range(0, 1000):
> mod = basis % div1
> if mod == 0:
> total = total + basis
>
On Sunday, April 20, 2014 10:43:37 PM UTC+4, Ivan Ivanivich wrote:
> hi all, i have simple programming task:
>
>
>
> [quot]
>
> If we list all the natural numbers below 10 that are multiples of 3 or 5, we
> get 3, 5, 6 and 9. The sum of these multiples is 23.
>
>
>
> Find the sum of all the
On 20 April 2014 20:27, Ivan Ivanivich wrote:
> thanks, i found the bag
G'day.
This [https://xkcd.com/979/] applies to threads ending in "nvm, solved
it" too. I know the problem in your case isn't likely to be widely
useful, but there are other benefits of pointing out what you've done.
For exam
On Sunday, April 20, 2014 10:43:37 PM UTC+4, Ivan Ivanivich wrote:
> hi all, i have simple programming task:
>
>
>
> [quot]
>
> If we list all the natural numbers below 10 that are multiples of 3 or 5, we
> get 3, 5, 6 and 9. The sum of these multiples is 23.
>
>
>
> Find the sum of all the
On Sun, Apr 20, 2014 at 3:02 PM, Chris Angelico wrote:
> On Mon, Apr 21, 2014 at 4:43 AM, Ivan Ivanivich
> wrote:
> > [quot]
> > If we list all the natural numbers below 10 that are multiples of 3 or
> 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
> >
> > Find the sum of all the mul
Ivan Ivanivich wrote:
> hi all, i have simple programming task:
>
> [quot]
> If we list all the natural numbers below 10 that are multiples of 3 or 5,
> we get 3, 5, 6 and 9. The sum of these multiples is 23.
>
> Find the sum of all the multiples of 3 or 5 below 1000.
> [/quote]
>
> this task f
On Mon, Apr 21, 2014 at 4:43 AM, Ivan Ivanivich wrote:
> [quot]
> If we list all the natural numbers below 10 that are multiples of 3 or 5, we
> get 3, 5, 6 and 9. The sum of these multiples is 23.
>
> Find the sum of all the multiples of 3 or 5 below 1000.
> [/quote]
>
> this task from http://pr
