Ah! Well! That explains it. I started to suspect that but (obviously) did
not know that. LOL
Thanks for your prompt reply, Grant. :)
-ej
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Use 'd' as the format character for 64-bit double precision numbers with struct.
>>> x = 148.73
>>> unpack(">> unpack("
pgpB2b9owxZs7.pgp
Description: PGP signature
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ej wrote:
> If that's true, then I guess I am confused why Python is displaying
> 148.72999572753906 when you unpack the 4 bytes, implying a lot more
> precision that was available in the original 32-bits? Python is doing
> 64-bit floating point here? I'm obviously not understanding somethin
On 2005-11-09, ej <> wrote:
> If that's true, then I guess I am confused why Python is displaying
> 148.72999572753906 when you unpack the 4 bytes, implying a lot more
> precision that was available in the original 32-bits? Python is doing
> 64-bit floating point here?
Yes. C-Python "float"
