Marc 'BlackJack' Rintsch <[EMAIL PROTECTED]> writes:
> Not exactly. In the case of no extension `os.path.splitext()` still works:
>
> In [14]: 'foo/bar.txt'.rsplit('.')
> Out[14]: ['foo/bar', 'txt']
>
> In [15]: 'foo/bar'.rsplit('.')
> Out[15]: ['foo/bar']
>
> In [16]: os.path.splitext('foo/bar')
On Sun, 27 Apr 2008 15:06:54 +, Matt Nordhoff wrote:
> Arnaud Delobelle wrote:
>> More simply, use the rsplit() method of strings:
>>
> path = r'C:\myimages\imageone.jpg'
> path.rsplit('.', 1)
>> ['C:\\myimages\\imageone', 'jpg']
>>
>>
> path = r"C:\blahblah.blah\images.20.jpg"
Arnaud Delobelle wrote:
> More simply, use the rsplit() method of strings:
>
path = r'C:\myimages\imageone.jpg'
path.rsplit('.', 1)
> ['C:\\myimages\\imageone', 'jpg']
>
>
path = r"C:\blahblah.blah\images.20.jpg"
path.rsplit('.', 1)
> ['C:\\blahblah.blah\\images.20', 'jpg']
>
Lie <[EMAIL PROTECTED]> writes:
> On Apr 27, 6:05 pm, Lie <[EMAIL PROTECTED]> wrote:
>>
>> I don't know if this is the simplest way, but you can use re module.
>>
>> import re
>> pat = re.compile(r'(.*?)\..*')
>
> Sorry, this line should be:
> pat = re.compile(r'(.*)\..*')
>
> or paths like these
On Apr 27, 6:05 pm, Lie <[EMAIL PROTECTED]> wrote:
> On Apr 27, 5:34 pm, wilson <[EMAIL PROTECTED]> wrote:
>
>
>
> > i was trying to convert all images in a folder to another type and
> > save the new images in a separate folder.for that i wrote a class and
> > coded some part
>
> > class ConvertIm
On Apr 27, 5:34 pm, wilson <[EMAIL PROTECTED]> wrote:
> i was trying to convert all images in a folder to another type and
> save the new images in a separate folder.for that i wrote a class and
> coded some part
>
> class ConvertImgs:
> def __init__(self,infldr,outfldr):
>
