In article <[EMAIL PROTECTED]>,
Johannes Bauer <[EMAIL PROTECTED]> wrote:
> David C. Ullrich schrieb:
>
> >> -- care to tell us what "a certain re.sub" is, and
> >> false in what way?
> >
> > Read the OP.
>
> Well, aren't you funny. Maybe you should have referenced the other
> thread so one c
David C. Ullrich schrieb:
-- care to tell us what "a certain re.sub" is, and
false in what way?
Read the OP.
Well, aren't you funny. Maybe you should have referenced the other
thread so one can find the OP?
Regards,
Johannes
--
"Wer etwas kritisiert muss es noch lange nicht selber besser
On 12 Jun 2008 12:32:13 GMT, Duncan Booth
<[EMAIL PROTECTED]> wrote:
>David C. Ullrich <[EMAIL PROTECTED]> wrote:
>
>> Practical question: What's a _complete_ list of the
>> escapes included in the "and so forth" in (**)?
>>
>> (Or is there a function somewhere that will convert
>> r"\remark{Hint
On Thu, 12 Jun 2008 14:12:31 +0200, Peter Otten <[EMAIL PROTECTED]>
wrote:
>David C. Ullrich wrote:
>
>> (Or is there a function somewhere that will convert
>> r"\remark{Hint}" to r"\\remark{Hint}" for me, and
>> do the same for precisely the escpapes referred to
>> in the "and so forth"?)
>
>I th
On Thu, 12 Jun 2008 05:12:55 -0700 (PDT), John Machin
<[EMAIL PROTECTED]> wrote:
>On Jun 12, 8:57 pm, David C. Ullrich <[EMAIL PROTECTED]> wrote:
>> True or False? (no fair looking it up)
>>
>> (*) If repl is a string then re.sub(pattern, repl, s)
>> returns s with non-overlapping occurences of pa
David C. Ullrich <[EMAIL PROTECTED]> wrote:
> Practical question: What's a _complete_ list of the
> escapes included in the "and so forth" in (**)?
>
> (Or is there a function somewhere that will convert
> r"\remark{Hint}" to r"\\remark{Hint}" for me, and
> do the same for precisely the escpapes
David C. Ullrich wrote:
> (Or is there a function somewhere that will convert
> r"\remark{Hint}" to r"\\remark{Hint}" for me, and
> do the same for precisely the escpapes referred to
> in the "and so forth"?)
I think you just have to escape the backslash:
re.sub(pattern, replacement_string.repla
On Jun 12, 8:57 pm, David C. Ullrich <[EMAIL PROTECTED]> wrote:
> True or False? (no fair looking it up)
>
> (*) If repl is a string then re.sub(pattern, repl, s)
> returns s with non-overlapping occurences of pattern
> replaced by repl.
>
> I assumed it was true - spent a few hours trying to
> fig
