Below is a function to get the current line number and file name.
/Jean Brouwers
- # dashes added to preserve indentation.
-
- import traceback
-
- def caller(up=0):
- '''Get file name, line number, function name and
-source text of the caller's caller as 4-tuple:
-(file, li
"Philippe C. Martin" <[EMAIL PROTECTED]> writes:
> All of the methods from my program return None on error (i.e; I do not
> want to assert and have the program exit).
>
> Is it possible to print the current source file name/line number ?
Someone else posted an example using an exception handler.
Philippe C. Martin wrote:
Hi,
All of the methods from my program return None on error (i.e; I do not
want to assert and have the program exit).
Is it possible to print the current source file name/line number ?
ex: in C/C++ I would use the macros __FILE__ and __LINE__.
Consider something like this:
