OK, totally dumb !
g_dict[s] = p
Philippe Martin wrote:
> Hi,
>
> I do not know if there is a way to overload the instantiation of all
> objects in Python but I thought of something like this to fetch any object
> with its name:
>
> g_dict = {}
>
>
> def create_object (v,s):
>p = v
>
Hi,
I do not know if there is a way to overload the instantiation of all objects
in Python but I thought of something like this to fetch any object with its
name:
g_dict = {}
def create_object (v,s):
p = v
g_dict[s] = id(p)
return p
#ex
object = create_object ([1,2,3,4], 'A LIST')
Ph
Thomas,
Thanks. I read about tuple packing and unpacking. Now I get to see it
in action. Plus, yours is one line shorter. If programming is anything
like writing, shorter is almost always better.
Thanks,
rick
--
http://mail.python.org/mailman/listinfo/python-list
I meant something like
def printdict(dictionaries=[(apps,'apps'), (dirs,'dirs'),
(sites,'sites')]):
for dictionary,name in dictionaries:
print name
keys = dictionary.keys()
keys.sort()
for key in keys:
print key, ":
BartlebyScrivener wrote:
> This works for now. I just added their names as values:
>
> def printdict(dictionaries=[apps, dirs, sites]):
>for dictionary in dictionaries:
> print dictionary["name"]
> keys = dictionary.keys()
> keys.sort()
>
>> Of course, the easiest way is just to use a tuple (dict,string).
I don't mean to be obtuse, but I'm not getting this one either. Is it
easier than what I did?
Thx,
rick
--
http://mail.python.org/mailman/listinfo/python-list
Here's an OO way that may do what you want:
>>> class MyD(dict):
... def __init__(self,dic,rep):
... dict.__init__(self,dic)
... self.rep = rep
... def __repr__(self):
... return self.rep
...
>>> apps = MyD({'alpha':1,'beta':2},'apps')
>>> apps
apps
>>> a
Yikes,
I'll have to come back to the OO way in a month or two ;)
This works for now. I just added their names as values:
def printdict(dictionaries=[apps, dirs, sites]):
for dictionary in dictionaries:
print dictionary["name"]
keys = dictionary.keys()
Wow,
That's food for thought. Thanks.
I see what they mean about change of approach. I'll just stick a key in
each dictionary called, er, name with its name value.
Thank you!
rick
--
http://mail.python.org/mailman/listinfo/python-list
Here's an OO way that may do what you want:
>>> class MyD(dict):
... def __init__(self,dic,rep):
... dict.__init__(self,dic)
... self.rep = rep
... def __repr__(self):
... return self.rep
...
>>> apps = MyD({'alpha':1,'beta':2},'apps')
>>> apps
apps
>>> a
BartlebyScrivener wrote:
> Still new. Learning attributes and functions and so on.
> Sorry if this is obvious, but if I'm defining a function for some
> dictionaries, how can I print just the names of the dictionaries?
Short answer: You can't.
http://pyfaq.infogami.com/how-can-my-code-discover-t
11 matches
Mail list logo