TG wrote:
> Okay, another one which I don't have answer for.
>
> it is the reverse case, sort of :
>
>> phi.shape (x,y)
>> d.shape (a,b)
>
> I want to return m :
>> m.shape = (x,y,a,b)
> with
> m[x,y] = d * phi[x,y]
>
> currently, my code is :
>> m = empty(phi.shape + d.shape)
>> m[:,:] = d
>
TG wrote:
> Hi there.
>
> I want to do some intensive computations with numpy, and I'm
> struggling a bit to find my wayy.
The best place to ask numpy questions is on the numpy mailing list.
http://www.scipy.org/Mailing_Lists
> Here is the problem :
>
> m and d are two matrices :
>
Okay, another one which I don't have answer for.
it is the reverse case, sort of :
> phi.shape (x,y)
> d.shape (a,b)
I want to return m :
> m.shape = (x,y,a,b)
with
m[x,y] = d * phi[x,y]
currently, my code is :
> m = empty(phi.shape + d.shape)
> m[:,:] = d
this repeats the matrix d x*y times,
