On Aug 13, 8:46 am, Sion Arrowsmith <[EMAIL PROTECTED]>
wrote:
> Dave <[EMAIL PROTECTED]> wrote:
> >hitNum = 0
> >stopCnt = 6 + hitNum
> >offSet = 5
>
> >for i in range(0,10,1):
>
> The step argument to range defaults to 1: it's tidier to omit it.
> Similarly, the start argument defaults to 0, so
Dave <[EMAIL PROTECTED]> wrote:
>hitNum = 0
>stopCnt = 6 + hitNum
>offSet = 5
>
>for i in range(0,10,1):
The step argument to range defaults to 1: it's tidier to omit it.
Similarly, the start argument defaults to 0, so you can drop that too.
for i in range(10):
> for x in range(hitNum,len
Dave wrote:
arrrggg, now I feel really dumb..
hitNum = 0
stopCnt = 6 + hitNum
offSet = 5
for i in range(0,10,1):
for x in range(hitNum,len(inLst), 1):
print hitNum, stopCnt
if x == stopCnt: break
hitLst.append(inLst[x])
hitNum +=o
Dave napisał(a):
> Hey there, having a bit of problem iterating through lists before i go
> on any further, here is
> a snip of the script.
> --
> d = "a1 b1 c1 d1 e1 a2 b2 c2 d2 e2 a3 b3 c3 d3 e3 a4 b4 c4 d4 e4 a5 b5
> c5 d5 e5"
> inLst = d.split()
> hitLst = []
>
> hitNum = 0
> stopCnt = 6 + hitN
arrrggg, now I feel really dumb..
hitNum = 0
stopCnt = 6 + hitNum
offSet = 5
for i in range(0,10,1):
for x in range(hitNum,len(inLst), 1):
print hitNum, stopCnt
if x == stopCnt: break
hitLst.append(inLst[x])
hitNum +=offSet
On Aug 13, 12:35 am, Larry Bates <[EMAIL PROTECTED]> wrote:
> Dave wrote:
> > Hey there, having a bit of problem iterating through lists before i go
> > on any further, here is
> > a snip of the script.
> > --
> > d = "a1 b1 c1 d1 e1 a2 b2 c2 d2 e2 a3 b3 c3 d3 e3 a4 b4 c4 d4 e4 a5 b5
> > c5 d5 e5"
Dave wrote:
Hey there, having a bit of problem iterating through lists before i go
on any further, here is
a snip of the script.
--
d = "a1 b1 c1 d1 e1 a2 b2 c2 d2 e2 a3 b3 c3 d3 e3 a4 b4 c4 d4 e4 a5 b5
c5 d5 e5"
inLst = d.split()
hitLst = []
hitNum = 0
stopCnt = 6 + hitNum
for i in range(hitNu
